Double substitution issue

[f***@gmail.com]

Thank you for explaining this fine point.

I have found a way to use double expansion, and of course this is not safe
in all contexts:

from=1;to=3;eval echo {$from..$to}

Regards,
Will

[Greg Wooledge]

Post by f***@gmail.com
I have found a way to use double expansion, and of course this is not safe
from=1;to=3;eval echo {$from..$to}

for ((i=from; i<=to; i++)); do
...
done.